Call for testing: OpenSSH 7.6

[Darren Tucker]

On 29 September 2017 at 15:47, Damien Miller <djm at mindrot.org> wrote:
> On Fri, 29 Sep 2017, Iain Morgan wrote:
>
>> Actually, according to OpenBSD's printenv(1) man page, it first appeared
>> in 2BSD. The man page on OS X claims it was BSD 3.0. However, it doesn't
>> appear to be part of any standard.

of the systems I have available here: the BSDs Linux and AIX have it.
Solaris doesn't have it in the standard path but it is in /usr/ucb.

>> Your suggestion ran into the same issue as the original test, but
>> escaping the evaluation by the user's shell appears to work:
>>
>> 'test -z `sh -c "echo \$SSH_USER_AUTH"`' || fail "SSH_USER_AUTH present"

Well escaping something for the user's shell depends on the shell's
escaping rules.

> How about:

Or how about we do the escaping on the client side where we know what
the rules are and feed it to /bin/sh over stdin?  Then it shouldn't
matter what the shell is.

test -z $(echo 'echo $SSH_USER_AUTH' | env SSH_USER_AUTH=blah ${SSH} -F \
       $OBJ/ssh_proxy x /bin/sh) || fail "SSH_USER_AUTH present"

-- 
Darren Tucker (dtucker at zip.com.au)
GPG key 11EAA6FA / A86E 3E07 5B19 5880 E860  37F4 9357 ECEF 11EA A6FA (new)
    Good judgement comes with experience. Unfortunately, the experience
usually comes from bad judgement.