No subject

I_PUSH
     Pushes the module whose name is pointed to by arg onto
     the  top  of the current stream, just below the STREAM
     head. If the STREAM is a  pipe,  the  module  will  be
     inserted  between the stream heads of both ends of the
     pipe. It then calls the open  routine  of  the  newly-
     pushed  module. On failure, errno is set to one of the
     following values:

Want to bet it's the "open routine" that acquires the controlling tty? If that's 
so the the only way I can see to fix it is push the STREAMS modules *after* 
forking to run the shell.

That cure might be worse than the disease.



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